You need to return values from your which() function
function which() {
if( b == "add" ){
return sum(p) ;
} else if ( b == "multiply") {
return mult(p);
} else {
return "sorry i cant do that";
}
}
console.log(which())
You already have that set up, what do you mean?
If 'add' is entered at the 2nd prompt then b == "add" is true and the sum(p) function will run. Same for mult. If something else is entered then it will output the else.
Global Universe
That's what I was trying to tell you in my first post. You should change the else statement to return the string instead of calling console.log() on it, and you should also parseInt(p) before sending it to the functions, so it is doing an implicit conversion.
let num = parseInt(prompt("Enter a positive number"));
let op = prompt("Enter add or multiply");
function sum(n) {
//Gauss formula for sum of 1-n
return (n+1)*n/2;
}
/*function mult(n) {
let product = 1;
for(let i = 1; i <= n; i++) {
product *= i;
}
return product;
}*/
function mult(n) {
if (n == 1)
return 1;
else
return n * mult(n-1);
}
function which() {
switch (op) {
case "add":
return "sum: " + sum(num);
break;
case "multiply":
return "product: " + mult(num);
break;
default:
return "Invalid option";
}
}
console.log(which());
