You will need to use two range for solving. Showed below:
# for x in range(1, n,2): [correction in code needed]
By using this approach also, you can solve it. However, you will need to take 2 range. Without range 1, n, 2 (won't get solved) 👇
n = int(input())
for x in range(1,n,2):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)
Ярослав Вернигора(Yaroslav Vernigora)
While solving I took reference from here:
Python's range() Parameters
The range() function has two sets of parameters, as follows:
https://www.pythoncentral.io/pythons-range-function-explained/
It has shown, how ranges works in conditioned for loops
range(stop)
stop: Number of integers (whole numbers) to generate, starting from zero. eg. range(3) == [0, 1, 2].
range([start], stop[, step])
start: Starting number of the sequence.
stop: Generate numbers up to, but not including this number.
step: Difference between each number in the sequence.
---------------
So, to skip even numbers in code... when we already have multiplie by 3 & 5.
We usually do even number with multiple of 2. This way, my problem was solved.
For increments we usually do something like "range(1, n+1)". I did it using [2 as step] in for loop.
Start with 1
Stop with n (input)
Step by using 2
Here is the correct code :
n = int(input())
for x in range(1, n):
if x % 2 == 0:
continue
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)
