Search engine project in python for beginners course
text = input()
word = input()
def search(text, word ):
if word in text:
print("Word found")
else:
print("Word not found")
print(search(text, word))
#All test caises fail because it outputs None added to the correct output. Plz. Help.
With 'print' inside a function, you don't need the outside one .It prints 'none' because the function do not return a value.
So, you have to remove the last print statement to avoid it.
search(text,word)
def seacrh(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
seacrh(text,word)
This will work 100%.👍
Try this:
text = input()
word = input()
def search(text, word):
#for i in word:
if word in text:
a ="Word found"
return a
else:
b = "Word not found"
return b
print(search(text, word))
def seacrh(text,word) :
if word in text :
print ('Word found')
else:
print('Word not found')
text = input()
word = input()
seacrh(text,word)
This will work 100%.👍
text = input()
word = input()
def search(text, word ):
if word in text:
print("Word found")
else:
print("Word not found")
print(search(text, word))
please help us by this code error
❤️😍Prerana 😍❤️ thought your code was correct and understood it so copy and pasted but it failed due to the print statement but thank you simple fix to a return statement
text = input()
word = input()
def search(text, word ):
if word in text:
return "Word found"
else:
return "Word not found"
print(search(text, word))
1. sentence=input("Enter a sentence:")
2. particular_word=input("Enter a particular word:")
3. def findin_word(sentence,particular_word):
4. if(particular_word in sentence):
5. return(particular_word + " is found in " +sentence)
6. else:
7. return("not found")
8. print(findin_word(sentence,particular_word))
It's only for knowledge.it will not work on sololearn project
