Count the number of zero's

Question

The program should output how many zeros are there!
here is my code!
what is wrong with it??
n = int(input())
sum = 0
for i in range(n):
if n == 0:
sum = sum+1
print(sum)
else:
print(0)
You can check my code in this link:
https://snakify.org/en/lessons/for_loop_range/problems/how_many_zeroes/
WARNING: just tell me why my code doesn't output the right thing
pleaseee

Answer 1

Can you add what is your expected output for a sample output?
Your this code prints n number of 0s only..(by else part)
edit:
Ailana
from the link, it is expected to
read n values and check how many of them are 0s.
but you are reading only 1st input.

Answer 2

You are just taking the first input which is N. There are no other inputs.
N = int(input())
zeroCount = 0
for n in range(N):
num = int(input())
if(num == 0):
zeroCount = zeroCount+1
print(zeroCount)

Answer 3

For sample input :
3
4
0
1
Your code :
n = int(input()) #this reads 3
sum = 0
for i in range(n): #this repeated i =0 to 2
if n == 0: #here 3==0 never true and executes else part.
sum = sum+1
print(sum)
else:
print(0)
What you need is : in loop read remaining inputs and check if it is 0 or not.
After out of loop print count value.
Ailana if you want ,To understand how loop works ,run this code and see output.
n = 10
for i in range(n):
print(i)
#outputs 0 to 9

Answer 4

range(n) generates a sequence 0, 1, 2, ..., n
That's not what you need
Treat the input as string, so no int() around it. Then loop through the characters:
for char in n:

Answer 5

Can u give me an example Jayakrishna?
Im sorry if i dont understand some things you tell me: :<

Answer 6

N -> this will tell you the number of input values that are going to follow.
N=5 means there is going to be 5 numbers.
5
18
0
67
0
48
This means there are 5 numbers.
18, 0, 67, 0, 48 and you must check that how many of them are 0's.

Answer 7

I know but what is wrong with my code up there on my question