Stuck at elif Statements V

Question

Here's what needs to be done:
elif Statements
Write a program that takes a number as input and
- returns its double, if the number is even
- returns its triple, if the number is odd
- returns 0, if number is 0
Here's what I have done:
number = int(input())
#your code goes here
if number // 2:
print(number + number)
elif not number // 2:
print(number + number + number)
elif num == 0:
print(num)
But the 4th one is still failing. Can someone please help me. Thank you!

Answer 1

For example if number is even like 4 then it will return 2 and if number is odd like 5 , then it will return 2.5 ,
therefore "if number//2" will be true for both odd and even ,so it never goes to next elif statements unless the number is 0.
Instead for even number check it as :
If number%2==0:
And for odd as:
if number%2!=0:

Answer 2

You don't want to use;
number // 2
This will end up being true in most cases, even when odd, as it will return the quotient from division of 2 as a result.
You want to use the modulo operator % and get the remainder of division instead.
if number == 0:
return 0
elif number % 2 == 0: #even
return number * 2
else:
return number * 3

Answer 3

Thanks, below the solution:
number = int(input())
#your code goes here
if number%2==0:
print(number + number)
elif number%2!=0:
print(number + number + number)
elif num == 0:
print(num)

Answer 4

num in the last branch is undefined. This gives no error because python is interpreted and that code is unreachable (0%2=0). So you can simplify:
if number%2==0:
print(number*2)
else:
print(number*3)