Please explain findOdd function in detail

Xor operation outputs 1 for operands with bit value 1 and 1 and outputs 0 for (1 and 0) and (0 and 0). Bit representation of 12 is 0001100 If you take another repeating number and perform xor operation between them , for example : 12=>0001100 12=>0001100 Output will be 0000000 So if you see , xor operation nulls repeated numbers ,thereby leaving non repeating number .

Thirt13n I know that and that's what keep the original bit alive. You are not messing with that bit . but wait for others answer.

You can understand this code here is my try: https://code.sololearn.com/crqn7demaUbT/?ref=app

Hey Abhay The result of XOR is 1 if the two bits are different.