import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
char[] result = new char[arr.length];
//store the result in reverse order into the result char[]
for(int i=0; i<arr.length; i++)
{
result[i] = arr[arr.length - i - 1];
}
System.out.println(new String(result));
}
}
Here I will check all testcases successfully
Why do people insist on doing things the hard way? Create a StringBuilder instance from your text string then reverse it...
StringBuilder sb = new StringBuilder(text);
sb.reverse();
System.out.println(sb);
https://docs.oracle.com/en/java/javase/14/docs/api/java.base/java/lang/StringBuilder.html
Using for-each for simplicity.
4 lines of code added.
https://code.sololearn.com/cig6PA96rplT/?ref=app
Your original code has splitted the String into an Char[] array.
For-each loop loops through the Char[] array, one Char (i) at a time, from left-to-right order.
String rev is the temporary result.
"rev = i + rev" means you are adding the i to the front, reversing the String.
Martin Taylor
The post is a coding question in SoloLearn, under Java, Arrays, after Module 3 Quiz (accessible only on mobile).
The existing codes have already split into char[] to demonstrate the understanding of Arrays.
One, in any queries, we should not be modifying the pre-existing codes. Two, for this case, we should not code using StringBuilder as that defeats the overall purpose of the Arrays lesson.
import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
for(int i=arr.length-1;i>=0;i--)
{
System.out.println(arr[i]);
}// Just we start printing from back side
}
}
