Int main (). { int i=20,j=10; if(I<10); I=i-5; j=j-5;printf("%d %d \n",I,j);

Why not try it? By the way there are some error I found like semicolons in " if " condition and some uppercases. https://code.sololearn.com/cA10A157A5A1

Ankit Kumar OK I know where you are getting into. You expect the output to be 15 5 right? Then it is because the if statement is False - - - - - - - - - - - - - - - i = 20 if (i < 10) - - -> This is False - - - - - - - - - - - - - Therefore the code below it will not be executed and the value of both i and j will not be substracted by 5. Make the value of i less than 10 to make it happen. I hope you now get it. Happy Coding!

Ankit Kumar, try it in the code playground please!

20 10

《 Nicko12 》just gave you the answer.

If there is semicolon after "if" statement the answer will be 15 5

It is because there is semicolon at the end of "if" statement that means the statements after "if" will execute irrespective of the condition

Are you not getting 15 5?

sai vamsi Yeah I also got 15 5 But in my first code it outputs 20 10 cause the if-statement is False and did not substract the numbers so... Ankit Kumar What output do you want anyway?

Yes Ankit Kumar output is clear it is 15 5. What are you expecting?

Wrong answer not 20 10

15 5

semicolon after if statement it is null statement and excute 15 5

Write sai

Ap code kar dekh ligye

Ankit Kumar Here output will be different. https://code.sololearn.com/cx6eHpQWM8nr/?ref=app

int main() { int i=20,j=10; if(i<10);---->semicolon means termination so this condition will not be considered . i=i-5;//i=15 j=j-5;//j=5 printf("%d%d",i,j); hence output will be 15,5

Any one can explain it