Binary Converter Java

Javi Tau Return as a String not int. Explanation:- As you are getting binary number as String so change return type int to String or convert String to int.

import java.util.Scanner; //your code goes here public class Program { public static void main(String[ ] args) { Scanner sc = new Scanner(System.in); int x = sc.nextInt(); System.out.print(Converter.toBinary(x)); } } public class Converter { public static String toBinary(int num) { String binary = ""; while(num > 0) { binary = (num % 2) + binary; num /= 2; } return binary; } } Here ya go m8

There is another way that code can be done, is like this and it keeps it looking the way they explained it in the in the challange public class Converter { public static String toBinary(int num) { String binary=""; while(num > 0) { binary = (num%2)+binary; num /= 2; } return binary; } }

import java.util.Scanner; public class Converter { public static String toBinary(int num) { String binary=""; while(num>0) { binary=(num%2)+binary; num/=2; } return binary; } } //ur code goes here public class Program { public static void main(String[ ] args) { Scanner sc = new Scanner(System.in); int x = sc.nextInt(); System.out.print(Converter.toBinary(x)); } }

If you pass input as 0 you will get runtime error. That is because you are parsing integer from empty string. And as I Am Groot! said return string since binary of even small numbers length will be very large.

Try... //tu código va aquí public class Converter { public static String toBinary(int num){ return Integer.toBinaryString(num); } }

does anyone know what the test #4 is? Cant pass this one only.

Where do you put the input number, without an ide I dont see it ? Sorry for such a noob question.

you dont, the test will do it for you

static StringtoBinary(int num){ String binary=""; while(num>0){ binary=(num%2)+binary; num/=2; } return binary

The binary converter import java.util.Scanner; //your code goes here public class Program { public static void main(String[ ] args) { Scanner sc = new Scanner(System.in); int x = sc.nextInt(); System.out.print(Converter.toBinary(x)); } } public class Converter { public static String toBinary(int num) { String binary = ""; while(num > 0) { binary = (num % 2) + binary; num /= 2; } return binary; } } Thid od the right answer

can someone explain line of code <String binary = "";>

import java.util.Scanner; //your code goes here class Converter { static int[] addToArray(int arr[], int x) { int[] newArray = new int[arr.length + 1]; for (int i = 0; i < arr.length; i++) { newArray[i] = arr[i]; } newArray[arr.length] = x; return newArray; } static int ArrayToInteger(int arr[]) { int Integer = 0; for (int i = arr.length; i > 0; i--) { int powerOfTen = (int)Math.pow(10, i - 1); Integer += arr[arr.length - i] * powerOfTen; } return Integer; } static int flipAndConvertToInteger(int arr[]) { int[] newArray = new int[arr.length]; for (int i = 0; i < arr.length; i++) { newArray[arr.length - (i + 1)] = arr[i]; } int output = ArrayToInteger(newArray); return output; } public static int toBinary(int x) { int[] binaryArray = new int[0]; int binaryRemainder = 0; do { binaryRemainder = x % 2; binaryArray = addToArray(binaryArray, binaryRemainder); x /= 2; } while (x != 0); return (flipAndConvertToInteger(binaryArray)); } } public class Program { public static void main(String[ ] args) { Scanner sc = new Scanner(System.in); int x = sc.nextInt(); System.out.print(Converter.toBinary(x)); sc.close(); } } My code's a little long, unfortunately, because I didn't see the string part and went the array way but it still doesn't clear the 4th test. Please help.