function main() { var amount = parseFloat(readLine(), 10); var rate = parseFloat(readLine(), 10); console.log(convert(amount, rate)); } function convert(a;b){ return = a*b; console.log(convert (100;1.1)) }
12/24/2020 12:54:55 PM
Alim Niyazov3 Answers
New AnswerAlim Niyazov , first you don't need to print with specific values =>console.log(convert(100, 1.1). Replace semicolons with commas between the function parameters and arguments. You can't say return = a * b. Instead write return a * b try this way : function main() { var amount = parseFloat(readLine(), 10); var rate = parseFloat(readLine(), 10); console.log(convert(amount, rate)); } function convert(a,b){ return a*b; }
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