How can I count the number of unique elements instead of show the unique elements? exp:in input show 4 .Means we have 4 unique

Question

#include<stdio.h>
#define max 100
int ifexists(int z[], int u, int v)
{
int i;
for (i=0; i<u;i++)
if (z[i]==v) return (1);
return (0);
}
void main()
{
int p[max], q[max];
int m;
int i,k;
k=0;
printf("Enter length of the array:");
scanf("%d",&m);
printf("Enter %d elements of the array\n",m);
for(i=0;i<m;i++ )
scanf("%d",&p[i]);
q[0]=p[0];
k=1;
for (i=1;i<m;i++)
{
if(!ifexists(q,k,p[i]))
{
q[k]=p[i];
k++;
}
}
printf("\nThe unique elements in the array are:\n");
for(i = 0;i<k;i++)
printf("%d\n",q[i]);
}

Answer 1

Sorry for the late reply!
You have already counted the unique number in your code, just have to print it out (value of k)...
Moreover i would highly recommend to use more handy variable names.. p, q, m, i, l, k... This is not really nice..
And some more spaces would be good, But this is a matter of opinion :)
I have refactored your code a little bit, and for sure added the requested print:
https://code.sololearn.com/c5HoR90ltWVx/?ref=app