Random Letter Checker

Question

I can pass 1, 3, & 4 tests for both ways. There is something I am missing because they both will not output “Deja Vu”. What am I overlooking?
Way#1
#test 1, 3, 4 passed
def repeating_letters?(str)
repeating_letters = gets
seen = [str]
str.each_char do |letter|
if seen.include?(letter)
return "Deja Vu"
else
return "Unique"
end
end
end
puts repeating_letters?("a..z")
Way#2
#test 1, 3, 4 passed
repeating_letters = gets
def repeating_letters(str)
for i in ('a'..'z')
if str.count(i) > 1
return "Deja Vu"
else
return "Unique"
end
end
end
puts repeating_letters("a".."z")

Answer 1

In both ways. You only test first letter, because you instantly return after as soon as the loop starts. Place return "Unique" out of the for loop and remove else statement.