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Zoo SQL Project challenge

Hi, I’m having difficulties with the last project. I get wrong result every time when I fix it. Can someone help me with the code or fix it? Thanks! /* name - "Slim", type - "Giraffe", country_id - 1 */ INSERT INTO Animals (name, type, country_id) VALUES ('Slim', 'Giraffe', 1); Select name, type, country from animals, countries

12/17/2020 9:23:56 AM

Bat-Ochir Artur

18 Answers

New Answer

+8

Thank you Ipang! I did it! Here’s my solution if you need it! /* name - "Slim", type - "Giraffe", country_id - 1 */ INSERT INTO Animals (name, type, country_id) VALUES ('Slim', 'Giraffe', 1); SELECT animals.name, animals.type, countries.country FROM animals, countries WHERE animals.country_id=countries.id order by animals.country_id desc

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INSERT INTO Animals (name, type, country_id) VALUES ('Slim', 'Giraffe', 1); SELECT name, type, country FROM Animals INNER JOIN Countries ON Animals.country_id = Countries.id ORDER BY country

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You mean output like this? Slim Giraffe 1 Slim Giraffe 1 Slim Giraffe 1 I would guess there are already some records in the table, all with same values. Probably the records entered in previous INSERT command. Oh well, good luck with solution then 👍

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No sweat bro 👌 Anyways, now that you mention another table, I guess you may find a need to use JOIN. https://www.sololearn.com/learn/SQL/1865/

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Hii MD SAIF I DID Try this and it works First Even I made same mistakes by putting "Where" at the place "ON" at which every time shows error at "WHERE" Then I take my time Step back at once check the " JOIN" functions in this, end realised that is wrong at "WHERE" in which syntax of "INNER JOIN"is something else than try one again and it work. If it's right than try,if it's wrong than leave it bro. Thanks you

+1

Still showing me an error, for some reason I get the output 3 times

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No bro this are all shows error at WHERE which is syntax error this is code code. Just replace at" FROM animals, countries" to " FROM Animals INNER JOIN Countries" And remove WHERE end place "ON" there Then all set. INSERT INTO Animals (name,type, country_id) VALUES('Slim', 'Griffe', 1); SELECT Animals.name, Animals.type, Countries, country FROM Animals INNER JOIN Countries ON Animals.country_id=Countries.id ORDER BY Animals.country_id DESC; Which run for sure if not please do same changes Thank you

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Just Copy and paste the below code, it will complete the use case of zoo SQL problem. _____________________________ insert into animals values ('Slim','Giraffe',1); SELECT initcap(a.name) as name, initcap(a.type) as type, CASE when a.country_id=3 then initcap('India') when a.country_id=2 then initcap('Russia') when a.country_id=1 then upper('USA') END AS country FROM Animals AS a inner join Countries AS c on a.country_id=c.id order by c.country Asc;

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SELECT name, type, country_id FROM animals How is this?

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When I do with country_id it works but I need with this format (name, type, country) but country is in another table. When I initialize countries table it and do (name, type, country) it outputs the table 3 times. like Slim Giraffe 1, slim giraffe 2, slim giraffe 3. Thanks for trying anyways bro!

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So whats the answer?

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Ipang, gw outputnya udah sesuai kok masih salah ya

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Hello, this is what worked for me: INSERT INTO animals (name, type, country_id) VALUES ('Slim', 'Giraffe', 1); SELECT animals.name, animals.type, countries.country FROM animals INNER JOIN countries ON animals.country_id = countries.id ORDER BY countries.country ASC;

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Small hint...worked for me after many failed attempts... make sure to capitalize first letters of Slim and Giraffe...

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What answer plz tell me

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All programs comes failure what problem I don't know,,😭😭need answers