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bruh

Fill in the blanks to define a function that prints "Yes", if its parameter is an even number, and "No" otherwise. even(x): if x%2 == 0: ("Yes") print("No")

1st Oct 2020, 3:32 PM
Isaiah Hudson
Isaiah Hudson - avatar
1 Answer
- 3
plz help me
1st Oct 2020, 3:34 PM
Isaiah Hudson
Isaiah Hudson - avatar