Send me if else statement code .the tuffest one | SoloLearn: Learn to code for FREE!

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Send me if else statement code .the tuffest one

Please

9/25/2020 2:44:28 PM

Round Up Kid

28 Answers

New Answer

+8

the variable coursework is not defined, so you get a NameError.

+3

Round Up kid.. in this code you have to define coursework... suppose coursework = "English" score_theory = 53 score_practical = 35 if(coursework == "Science" or coursework == "science"): if(score_theory > 50): print("Please check the input score for 'Science: Theory'.") elif(score_practical > 50): print("Please check the input score for 'Science: Practical'.") else: print("Score validated for Science. Your total is: ",score_theory + score_practical) elif(coursework == "English" or coursework == "english"): if(score_theory > 60): print("Please check the input score for 'English: Theory'.") elif(score_practical > 40): print("Please check the input score for 'English: Practical'.") else: print("Score validated for English. Your total is: ",score_theory + score_practical) else: print("Coursework not recognised. Please enter score for either Science or English.") now this will work..!!

+2

No..! u'll get a name error

+2

Iron Man Indent it properly... x=man If x==man: Print ('yes') else: Print('no') This one works out....

+2

Round Up Kid check out this one... guessing_number =100 user_type = int(input("guess a number")) if user_type == guessing_number: print("you win") else: if user_type < guessing_number: print("too low") else : print("too high")

+2

It is working thank you

+1

Yes Now it says different things I don't know it is working or not But no error now

+1

Thank yoi

+1

For every bit of code, therer can be a more complex one.

+1

Iron Man thank you

+1

#plz correct my code guessing_number =100 user_type = int(input("guess a number")) if user_type == guessing_number: print("you win") else: if user_type < guessing_number: print("too low") else : print("too high") #plz correct my code

+1

Nguyễn Thành Trung I get error of intendention I don't know why but I press tab button then also But it's okay now every thing is fine

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Thank you

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Unfortunately it's not working Maybe it's my pydriod It's not working if else statement

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No it's not running

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Traceback error

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score_theory = 53 score_practical = 35 if(coursework == "Science" or coursework == "science"): if(score_theory > 50): print("Please check the input score for 'Science: Theory'.") elif(score_practical > 50): print("Please check the input score for 'Science: Practical'.") else: print("Score validated for Science. Your total is: ",score_theory + score_practical) elif(coursework == "English" or coursework == "english"): if(score_theory > 60): print("Please check the input score for 'English: Theory'.") elif(score_practical > 40): print("Please check the input score for 'English: Practical'.") else: print("Score validated for English. Your total is: ",score_theory + score_practical) else: print("Coursework not recognised. Please enter score for either Science or English.") # I tried pydriod 3 app I also try solo learn app nothing works #maybe it's my personal app problem #how can I fix this?

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wht error exactly u are getting?

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Traceback error

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I have screenshot uploading in web There you see what problem I'm facing Wait