Pythagoras theorem / Else Statements (Python)

Question

Else Statement
Pythagoras theorem says: In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides.
Write a program that takes lengths of triangle sides as inputs, and output whether our triangle is right-angled or not. If the triangle is right-angled, the program should output "Right-angled", and "Not right-angled" if it's not.
Sample Input
3
4
7
Sample Output
Not right-angled
[Take the 3rd input (side3 variable in sample code) as the longest side, which will represent the hypotenuse if the triangle is right-angled.]
________
My solution:
side1 = int(input())
side2 = int(input())
side3 = int(input())
#your code goes here
side1 *= side1
side2 *= side2
side3 *= (side1 * side1) + (side2 * side2)
if side3 <= (side1*side1) + (side2*side2):
    print("Right-angled")
else:
    print ("Not right-angled")
__________
My solution works for 2 tests, but not the other 2..

Answer 1

This should work.
isRightAngle = side3**2 == (side1**2 + side2**2)
print("Right-angled" if isRightAngle else "Not right-angled")

Answer 2

I received the answer courtesy of @Steven M
side1 = int(input())
side2 = int(input())
side3 = int(input())
#your code goes here
if (side1**2) + (side2**2) == side3**2:
print("Right-angled")
else:
print("Not right-angled")

Answer 3

Zone and what difference between side1*side1 and side1**side1?

Answer 4

Petr either way only 2 of 4 tests say it's correct

Answer 5

Petr the extra "*side1" isn't necessary I'm assuming?

Answer 6

Thanks for everyone who helped and tried to help ✊🏾

Answer 7

I messaged him directly for help.. for some reason I can't tag him in the discussion.

Answer 8

side1 = int(input())
side2 = int(input())
side3 = int(input())
if (side1 **2) + (side2 **2) == (side3 **2):
print("Right-angled")
else:
print( "Not right-angled")
My solution works for 4 tests

Answer 9

if side1**2 + side2**2 == side3**2:
print("Right-angled")
else:
print("Not right-angled")

Answer 10

Zone is side1**side1 a square of side1? For example side1==25..

Answer 11

Petr yes

Answer 12

Petr I guess that's a mistake, I don't need the **

Answer 13

Zone ** is exponentiation, and * is multiplication

Answer 14

Zone ок. Then at first you did side1*=side1, then in if you write side1*side1. So i have side1**4. :)))

Answer 15

Zone Can you put your code in your profile?

Answer 16

Zone i just ask you. But you maybe right:)))

Answer 17

Petr ?? what do you mean? It's in the post already

Answer 18

Isn't the question asking this =>,
if side3*side3==side1*side1+side2*side2:
right angled
Else
Not right angled
I am trying to understand what is
side3*=(side1*side1)+... doing
Also why <=?
according to the last calculation of yours ,side3 has the largest value now ,so <= will never work lol!

Answer 19

Ore your answer works too... 👍🏾

Answer 20

Ore since he wasn't in the discussion I marked your answer as best answer 👍🏾