why isnt it working?

Question

https://code.sololearn.com/ctsx1TChvvZC

Answer 1

You also compare same elements with each other (e.g. index 0 with index 0). Btw. you should take a look at foreach-loop in Java, use the equals-method to compare strings, and rename the method to countDuplicates. And remove the unnecessary and totally wrong inner third loop.

Answer 2

if (arr[i].equals(arr[j])){
checkForDups++;
}

Answer 3

Basically you missed to skip i == j

Answer 4

Sandra Meyer thanks!!!

Answer 5

Sandra Meyer , whats the problem now?
code:
import java.util.*;
public class Main
{
public static void main (String[] args){
final String[] myArr = {"banana" , "apple" , "apple"};
countDuplicates(myArr);
}
public static int countDuplicates(final String[] arr){
int checkForDups = 0;
for (int i = 0; i < arr.length; i++){ //this loop is for going through the array
for (int j = 0; j < arr.length; j++){ //this one also... ^
if (arr[i].equals(arr[j])){
checkForDups++;
}
}
}
return checkForDups;
}
}

Answer 6

I'll make a clean version of that for you, please wait 😉⏳

Answer 7

https://code.sololearn.com/cDwnjSa0DBte/?ref=app

Answer 8

And another point, since you're in fact counting all duplicates twice: Divide your count afterwards! 😉
return value / 2;

Answer 9

wow, ok. thanks! but what does this part do: i!=j
?

Answer 10

Well, if you have { "banana", "apple" } and then compare arr[0] with arr[0], then you'll find, that banana == banana, but this is not, what you want to count!