C++ cout

Question

Can i output arguments with "cout" in this way:
cout << a,b;
When i write so, then the compiler writes only argument a. It works like this:
cout << a << b;
but i want to know why i cant use the first variant.
(Sorry for my bad english)

Answer 1

Thats why you cant.
See how i made grammatical errors. It basically the same thing. You need to write the correct syntax