Answer 1

👍

Just to put it explicit:

Because int() can accept string such as "123" but it cannot accept string such as "".

So in version 2, the error "base 10" appears, when your input1 is "" and the line int(input1) is reached.

And in version 1, your if conditon is preventing int("") to happen, so there won't be the error message.

Answer 2

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥
if int(hours) >= a:
print("yes")
also
if int(hours) == a:
print("yes")

Answer 3

What do you see with
int("")?

Answer 4

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 error is not in this case!
If you give no output or not a number, then the int part will show an error!
print(len(str("")) == 0)
Is not where your code is wrong

Answer 5

Try starting a blank code
and run with only

int("")

Answer 6

What does it say?

Answer 7

Why are you using 'int' in the first condition and 'len' in the second?

Answer 8

What do you want to achieve? Can you give some input - output pair examples

Answer 9

What does it mean?

Answer 10

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 Is your question solved already?

Answer 11

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 let's look at this a bit different as int is a float not a natural number though it may appear to look as such thus you are trying to compare them as equals....

https://code.sololearn.com/cSIq2GujVmvf/?ref=app

Answer 12

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 your order of operations were skewed
input1=input()
if not input1:
print("input1: Please enter a value")
elif int(input1)>=1001:
print("Input must be less than 1000")
else:
print("Input1 :",input1)

Answer 13

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥
In your second version,

after input1 = input()
add
print(input1)

what do you see?

Answer 14

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 You are right

Answer 15

𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 the second code is not addressing len but base '10' error

Answer 16

Use try and except in these cases
Instead of using if elif and else

Answer 17

import re

pattern = r"spam"

if re.match(pattern, "spamspamspam"):
print("Match")
else:
print("No match")

Answer 18

You will have to convert it into a string then find its length!

See this! This will help you
https://code.sololearn.com/cu97E23K8Zmg/?ref=app

Answer 19

Have a look at this!
If the input is empty then it will show an error

https://code.sololearn.com/cpZ4gT214aHe/?ref=app

Answer 20

I think you you have already understood the error by now.
Your second code can be fixed by adding "0" to input1 in the 1st if block. Like this:

if int(input1 + "0") >= 1001: