why is result 25 when the sum in fact 23?

Question

#include <stdio.h>
int main() {
int count = 11;
int ssumm;
while (count <= 18) {
printf(" Count = %d\n", count);
printf (":\n ");
count++;
ssumm = ssumm + count ;
if (count == 13)
break ;
}
printf (" iam zasum just afta zalup ova %d\n", ssumm );//result is 25?
return 0;
}

Answer 1

When loop will run first time then 11 will print in first then count++ it will increase by 1 and it will become 12
ssumm=0+12; so ssumm=12 then again loop will run
count ++ so present value of count is 13
ssumm=12+13 so answer is 25

Answer 2

ssumm is unintialized, so lets assumming its 0.
in first step
ssumm = ssumm + count;
12 = 0 + 12
in second step
25 = 12+13
now count is 13, so break

Answer 3

First it ran with 11.
Satisfied the while loop.
When you incremented count++
Count became 12.
Sum was initially 0 but now is 12.
Again satisfied while loop with count = 12.
Incremented to 13.
Sum: which was 12 before added to 13, and that makes 25.
Now that count = 13 broke out of while loop.
Finally prints sum=25.

Answer 4

12 +13 =25

Answer 5

thnx friendz