What is the output of the following code?

Question

nums = {2 : 'two', 1: 'three', 3:'four'}
for each in set(nums.keys()):
if nums[each] > 'four':
print(each)

I'm not sure if the output will be 21 or 12 because I'm unaware of the order of keys in the set that's iterated on.

Answer 1

You can directly iterate on the dict.keys without using a set. In the code set is used to avoid duplicates? The keys are also unique , so you can work without using a set.
But what you are comparing with: if nums[each] > 'four'? So you compare for example 'two' > 'four'. You need to explain this 😉😃

nums = {2 : 'two', 1: 'three', 3:'four'}
for each in nums.keys():
if nums[each] > 'four':
print(each)

Answer 2

RAJESH SAHU, a set does not necessarily puts the numbers in sorted order. If you try this:

print(set([66,120,15,997,334,1024]))

the result will be:

{1024, 66, 997, 334, 15, 120}

Answer 3

Lothar, thank you for the response on an alternate way of writing the code.
But please look at it as a question on the output and not on the implementation.

Answer 4

Answer will be:
1
2

As set arrange the values in the ascending order