Is it possible to cast a void pointer to the type of its content?

Question

I mean something like this,
bool b;
void* ptr = &b;
cout<< *( type(b)* )ptr;

Answer 1

Well yea
bool b = true;
void* p = &b;
std::cout << *(decltype(b)*)p;
But this only applies if b is in scope and you know where p is pointing to.
Most of the time you'll want to avoid void* unless you know what you're doing.