Python (IF statements)

Question

What is the output of this code?
num = 7
if num > 3:
print("3")
if num < 5:
print("5")
if num ==7:
print("7")

the ans is 3 ..
my question is why it is not 37?

Answer 1

Because variable num is not less than 5, So num < 5 the condition fails and the indented code will won't execute
----------------------------------------
num = 7
if num > 3:
print("3")
if num < 5:
print("5")
if num ==7:
print("7")

The above will make output 37

----------------------------------------------

NOTe:
space
matters in
python

Answer 2

It is because when it reached
if num > 3:
print ("3")
the if loop closed and 3 is printed as
if num < 5:. is FALSE
So the conditions after it would not be carried out!

Answer 3

num = 7 #1
if num > 3: #2
print("3") #3
if num < 5: #4
print("5") #5
if num ==7: #6
print("7") #7

Now as num is 7, #2 condition is true, so 3 will be printed.
Next, #4 condition is false so the control will jump out of that suite (block of code)
#6 condition comes under #4 indent. So #6 will execute only if #4 is True.
So answer is 3
And not 37

Answer 4

Because of when your loop reach at
if num>3: your computer has to stop computing before and give the answer that is 3.

Answer 5

The 'if' statements should be indented using equal spaces. 'elif' and 'else' statements should also fall in the same line as the if statements
for example
x=input("Enter x: ")
num1=int(x)
print(num1)
if num1<=60:
print("Pass")
elif num1>=60:
print("Good")
elif num1>=70:
print("Excellent!")

Answer 6

each time you indent, the code must meet the if requirements before it to run. youre telling the computer if 7 < 5, follow these commands. so it doesnt print “7” because it just skips the code in that section