Who can answer ???

Question

Allow a user to input 6 integer numbers into array Y. Then, by using pointer, go through the array elements to find the sum and the average of values divisible by 5 in the array contents. Finally, print on the screen the array contents, the sum and the average. By using #incloud<iostream>
.
And this my wrong try ...
#include <iostream>
using namespace std;
int main()
{
int y[30], i;
cout<<" enter the numbers of array ";
for (i=0 ; i<6 ; i++)
cin>>y[i] ;
int *ptr ;
ptr=&y[0];
int sum=0.0 ;
for(i=0 ; i<6 ; i++)
{if (i%5==0)
sum=sum+(*(ptr+i));
float avg=sum/6 ;
cout<<"the sum = "<<sum<<"\n"<<"the average = "<<avg;}
return 0; }

Answer 1

u r welcome 😊

Answer 2

first in this loop you should check on the values not position
so you should write
if((*(ptr+i))%5==0)
then to know the sum and the average, you don't need them into the loop so you write avg and printing operation out of loop
and you need counter to know how many values divisible by 5 to calculate the average
*Don't forget to check if this counter equal 0 or not to avoid dividing by 0
the solution is
int count=0;
for(i=0;i<6;i++){
if((*(ptr+i))%5==0){
sum=sum+(*(ptr+i));
count++;
}
}
float avg;
if(count==0)
avg=0;
else
avg=sum/count;
cout<<"sum="<<sum<<"\naverage="<<avg;

Answer 3

thank you very much 👏

Answer 4

check the messages please 🙏