for go language : can anyone tell me how the starting job is printing without printing finished job exactly after that

Question

package main
import (
"fmt"
"time"
)
func worker(id int, jobs <-chan int, results chan<- int) {
for j := range jobs {
fmt.Println("worker", id, "started job", j)
time.Sleep(time.Second)
fmt.Println("worker", id, "finished job", j)
results <- j * 2
}
}
func main() {
const numJobs = 5
jobs := make(chan int, numJobs)
results := make(chan int, numJobs)
for w := 3; w >= 1; w-- {
go worker(w, jobs, results)
}
for j := 1; j <= numJobs; j++ {
jobs <- j
}
close(jobs)
for a := 1; a <= numJobs; a++ {
<-results
}
}
// Output :
worker 1 started job 1
worker 3 started job 2
worker 2 started job 3
worker 1 finished job 1
worker 1 started job 4
worker 2 finished job 3
worker 2 started job 5
worker 3 finished job 2
worker 1 finished job 4
worker 2 finished job 5
i understand nearly all the problem how its working but just the part that the started & finished job are not printing consecutively

Answer 1

i have got the answer but are anyone else is following this question