how do i jump or to shuffle the next value in a list?

Question

count = 0 # counter after the solution should be 7
a = ['1', '2', '3', '3', '5', '5', '6', '6', '7', '9'] # 5<->7 and 6<->9
b = ['0', '0', '2', '2', '3', '6', '6', '6', '7', '9']
count+=1 <<if a[i]>b[i]
iterating through both the list together, whenever a[element]<b[element], i want to shuffle the current a[element] with a greater that is greater than the current b[element] too..
As in above case,
a[elements] are greater than b[element] until a[5] comes during iteration, because a[5]<b[5]...so what i wanna do is find the next element in the "list a" which is greater than b[5] i.e 7..and shuffle 5 and 7 in the list 'a'.and comare with the current element in "list b"......and same for the further elements until list is over...
and count+=1 when a[element]>b[element]...
in the above case, count must be =7, because of shuffling 7 and 9 in "list a"
hope you understand what i am trying to tell you!

Answer 1

@Amit Dubey
I wrote it, but it is not a good idea to use it without understanding it. I put a lot of comment to help you to understand, so please take some time to do this :)
https://code.sololearn.com/c4FZFwso93VZ/#py

Answer 2

So you want that a[i] > b[i], except for the last few elements ? So that in this case, a = [1, 2, 3, 3, 5, 7, 9, 5, 6, 6]
If yes, I can help you, else, please help me to understand what you want first :)

Answer 3

Kinda like that..but a lil change...
a = ['1', '2', '3', '3', '5', '7', '9', '6', '5', '6']...put the element to be swapped i.e 5 at the place of 7..and 6 at the place of 9...
SpaceNerd

Answer 4

a = [1, 2, 3, 3, 5, 7, 9, 5, 6, 6]
This can work too, i guess..gimme a code plz SpaceNerd

Answer 5

Wow... that's some great explanatory skills you got!
Thank you so much!😊 SpaceNerd