Why is the result 8?

Question

list = [1, 1, 2, 3, 5, 8, 13]
print(list[list[4]])

Answer 1

list[4]=5 #note that indexing starts from 0.
Now list[5]=8

Answer 2

When we print(list [4]) we get 5 as output
. It's in the forth postion . I think u know that it's postion starts from zero. So in thies it will first evaluate s the list [4] and the result of that is 5 next it will evaluate list [5] so the output is 8 .
In the above code u can understand easily.

Print(list[list [4]])
# list[ 4 ] becomes 5
Print (list [5])
👉8

Answer 3

list[4]=5
list[5]=8
print(list[list[4]])
print(list[5])

output

8

Firat inner list[4] is calculated than outer list[5]

Answer 4

still, don't get it

Answer 5

list[4] means value at 4th index and the index starts from 0.
So value at 4th index is 5.

Now list[list[4]] = list[5] because we have solved it as shown above. Now value at 5th index is 8.

Hope it's clear now.

Answer 6

list[list[4]] = means list[5] ?
so
list[list[1]] = list[2] correct?

Answer 7

So why the result is 2 for this?

list = [1, 1, 2, 3, 5, 8, 13]
print(list[list[2]])

Answer 8

Dean Bartusek
No,

list[4] give us element of list of index 4.that is 5.
Than in outer list this 5 becomes list[5] now element at index 5 in your list is 8.

If you still couldn't understand than I suggest you to first complete list lesson on sololearn

Answer 9

Dean Bartusek you have not understood indexing well. Take a look at this link https://www.hackerearth.com/practice/notes/samarthbhargav/a-quick-intro-to-indexing-in-JUMP_LINK__&&__python__&&__JUMP_LINK/

Answer 10

see now, thank you

Answer 11

list[4] evaluates as 5
making the expression list[5]
which evaluates to 8

Answer 12

Because of indexing on the inner list[4] the position is number 5 so on the outer list its list[5] and the indexing position 5 is number 8

Answer 13

The first list[] started counting at 0 then the second list[] started counting at 1 then to 5 because list[list[4]] returns index 5.