unary operators : If float x; then x=sizeof(double) then why out is 0

Answer 1

Because you use wrong format specifier. %d is used for `int` data. But you are actually printing `float` data. Use %f instead of %d, and it will work 👍

Answer 2

Thanks you for helping me 👍👍👍

Answer 3

No problem buddy 👌
And for further introduction on format specifiers, you can check these out 👇
http://www.cplusplus.com/reference/cstdio/scanf/
http://www.cplusplus.com/reference/cstdio/printf/

Answer 4

Why out is 0? I don't know. In your code you don't seem to be printing anything out. But assuming you did print the <x> value, how did you do it?

Answer 5

#include<stdio.h>
Main()
{
float x;
Clrscr();
X=sizeof (double);
Printf(''%d",x);
getch();
}
This is the program
Why output is 0 when float contain 4 byte and double contain 8 byte