Copying one string to another ignoring some characters.

Question

Hello Everyone, The idea is to get a user input in the form of a string representing a money amount like
“$1,234,567.45" and then copy it into another char array ignoring the "

Answer 1

Imagine, if comma found at index 6 but, your character array Mon[50] have already stored only 3 elements but, it will skip to index "i" and stores given value, this is what mistake you did.
Solution:
Make saparate variable to assign values to another array.
int index = 0;
for(size_t i = 0; i<M.length(); i++){
if(M[i]!='#x27;&&M[i]!=','){
Mon[index] = M[i];
// & then, increase the value of "index" for next element to store.
index++;
}
}
Hope this helps!

Answer 2

thank you very much.

Answer 3

I haven't used it in c++ yet however what you're looking for is Regular Expression or RegEx
In java (for example) you can filter out symbols, letters or numbers using regex
Sample:
String reg = "$600.77";
String out =
reg.replaceAll("[$ \.]", "");
System.out.print(reg);
Output:
60077
Try this link:
https://regular-expressions.mobi/stdregex.html?wlr=1