How to return indices of two numbers that sum of these numbers equal to 9?

Question

for example: array [2, 7, 11, 15], and it is necessary to return index [0] and index [1] because sum of it equal 9.
my code:
nums = [2, 7, 11, 15]
comb = [(x+y) for x in nums for y in nums if x!=y]
offset = 0
for item in comb:
if item==9:
offset += 1
print(enumerate (x))

Answer 1

I am not quite sure what you suppose to get by "print(enumerate(x)", but this expression is not valid, becuase enumerate can only be used with iterables. May be this can help you:
nums = [2, 7, 11, 15]
comb = [(x+y) for x in nums for y in nums if x!=y]
offset = 0
for ind, item in enumerate(comb):
if item==9:
offset += 1
print(ind)

Answer 2

Can you show us your attempt ?

Answer 3

Andrex can you post it here so we can tale a look at it ?

Answer 4

Maybe something like this?
nums = [7,11,2,15,-2]
l = len(nums)
for i in range(l):
for j in range(l):
if i != j and nums[i] + nums[j] == 9:
print(i, j)

Answer 5

it works, many thanks!!!)

Answer 6

i have added my code, but it doesn't work correct

Answer 7

nums = [2, 7, 11, 15]
comb = [(x+y) for x in nums for y in nums if x!=y]
offset = 0
for item in comb:
if item==9:
offset += 1
print(enumerate (x))

Answer 8

Your code returns indexes 0, 3, but we need to return 0, 1

Answer 9

You're welcome 👌

Answer 10

Lothar, What I need to do to return indexes from "nums" array in your code? because your code return indexes from comb