About the Average Word Length problem | SoloLearn: Learn to code for FREE!

+8

About the Average Word Length problem

I am struggling with this problem since yesterday. I did what i can do, but I couldn't get 5/5. No matter what i did, I always get 3/5. can you see what I'm missing in this code? # as a remainder, the average word length problem is: you have an input with multiple words, and the output should be the average of letters per word rounded to the nearest whole number. And Here's the code: import string punc= string.punctuation test= input() phrase=" " count_letter =0 count_word =0 for i in range(len(test)): phrase +=str(test[i]) if phrase[i] == " ": count_word +=1 if phrase[i] != " " and (phrase[i] not in punc): # not counting spaces and punctuations count_letter +=1 print(round((count_letter +1)/count_word))

1/3/2020 12:41:27 AM

AbdullaH

24 Answers

New Answer

+7

Try using: (count_letter//count_word)+1 Also, im really glad i read your question. i had no idea there was a string library. I used regex to solve this.

+6

Your code adapted. I bypassed the word =" ", and iterated directly from the input. Also a minor change to word_count = This now works. Thanks heaps for sharing your interesting concept https://code.sololearn.com/cdm958D8hhbU/?ref=app

+4

Aymane Boukrouh has hit the nail on the head. The task requires you to "round up" to the nearest whole number.

+4

I am also playing with the code and getting some discrepancies when I introduce an extra " " space into the sentence. The code counts an extra word each time it sees chr(32), " ".

+3

Try using math.ceil() instead of round()

+3

also you can’t use the code i gave you for rounding because if you floor a number like 3.0 it becomes 3.0. And then you add 1, it becomes 4. math.ceil() is the right choice. But thats not the issue. ——————-Spoiler ahead: The issue starts all the way at the beginning of your code with the line phrase = “ “ because then you do: phrase += str(test[i]) That means phrase is now “ word” Which means phrase[i] = “ “ And your if statement says if phrase[i] = “ “ then add a word!!! To solve your issue, all you have to do is is change: phrase = “ “ to: phrase = “” And you’re done. Lol, coding can be so cruel. All this over a damn whitespace.

+2

It did surely made a difference. I'm now getting 4/5, but now a new problem came out. The (count_letter) part, when doing ((count_letter +1)/count_word) test 5 fails. And when instead doing (count_letter/count_word) test 1 fails 🤷‍♂️.

+2

Ivan thank you, but it didn't fix the second problem.

+2

ok so i figured out your problem. First use the code that shows you the failing test case like the one i gave you. Here’s a copy of your code that i changed a little. Run it on your end and you will see what is happening that is causing you to round incorrectly.

+2

import string punc= string.punctuation test= input() phrase=" " count_letter =0 count_word =0 for i in range(len(test)): phrase +=str(test[i]) print("character: " + phrase[i] + " ~ ") if phrase[i] == " ": count_word +=1 print("Adding a Word") elif phrase[i] != " " and (phrase[i] not in punc): # not counting spaces and punctuations count_letter +=1 print("Adding a Letter") print(round(((count_letter)//count_word)+1))

+2

To round up to the next number you can use ceil() in the math module. from math import ceil print(ceil(4.1)) # output: 5

+2

https://code.sololearn.com/c3tFNP5i63Vp

+2

you have to remove the floor and replace it with ceil and get rid of the + 1 right now you are doing this: 13//3 = 3.0 + 1 + 1 = 5 i just copied yours and removed that and it worked. edit: nope. i was using the old one you wrote. Davids code is good for learning more methods, but i think you should try to make your code work. It’s almost there. I’ll post mine as well above yours. Your missing two conditional statements.

+2

Ivan Thanks, I don't know if it does work because I copied the code David Ashton wrote to test it and it worked. But it is a completely different approach.

+1

'''#My Answer: import re,math as m x = list(map(lambda y: len(y), ''.join(re.findall('[A-Za-z ]',input())).split(' '))) print(m.ceil((sum(x)/len(x)))) ''' import string import math punc= string.punctuation test= input() phrase= "" count_letter =0 count_word =0 for i in range(len(test)): phrase +=str(test[i]) print(phrase + "-----------") if phrase[i] == " " or phrase[i] in punc: count_word +=1 print("Add a word") if phrase[i] != " " and (phrase[i] not in punc): count_letter +=1 print("Add a letter") # you need to check to see if the before a punctuation there is another punctuation. like “Hello there...” print(math.ceil(count_letter/count_word))

+1

Try my code: Average word length: import string import math punc= string.punctuation test= input() phrase= "" count_letter =-1 count_word =1 for i in range(len(test)): phrase +=str(test[i]) if phrase[i] == " ": count_word +=1 if phrase[i] != " " and (phrase[i] not in punc): count_letter +=1 print(math.ceil((count_letter//count_word)) +1)

+1

word = input() str = word.split() import re, math mystr = re.sub(r"[^A-Za-z]", "", word) print (int(math.ceil(len(mystr)/len(str))))

0

Ivan, it didn't work. Apparently, it made it worse, now I'm getting 1/5. I'm sure I wrote everything right..

0

Ivan https://code.sololearn.com/cc2lYrQ8XlaQ/?ref=app Here's the code

0

David Ashton I did it but it didn't fix the second problem.