What will be the output when Method(3) is invoked?

Question

void Method(int c)
{
if(c==0)
System.out.println(" ");
else
{
System.out.println("Hello"+c);
Method(--c);
System.out.println(" "+c);
}
}

Answer 1

If you want explanation or reason , briefly
The last Method(0) call will complete first by printing 0 by last statement. And first call Method(3) last..

If you have problem in executing, then run it playground and share link here. Then some correct your mistakes if any....

Answer 2

If you want output then,Why cant run this in code play code? pls Clearly specify what you need there ?
Any way the output
It give as
Hello3
Hello2
Hello1
0
1
2
It include spaces also as in your code...

Answer 3

I said compilation error....

How can you expect output without proper details? Sry It's not possible by me.

edit : √

Answer 4

Read the comments there, in that program. Explanation is there. And i posted link in code comments which gives you full information..
hope that clears...

Answer 5

Its definition doesn't matter.
Answer is asked of this code only,it doesn't need entire program

Answer 6

Sorry! I have corrected the question.
Answer it again.

Answer 7

I understood 👍
I was also getting this output but I was a little bit confused.
This question was asked by my computer teacher.

Answer 8

Can you explain that Robo program that I have recently seen on your timeline

Answer 9

Where is Method(3) definition?
It compile error raises..
void(int c) not a proper function specification. ..
what you are trying here? can you explain?

edited : question √