array of types

Question

can I have a map of types ?
I have an array of pointers to a base class
every element refers to a son of this base
I want to type cast to the son with something like map of array
so instead of doing that
if(a[i]->gettype()=="type1")
((type1*)a[i])->doit();
else if(a[i]->getttype()=="type2")
((type2)a[i])->doit();
I want to do something like
((type[k])a[i])->doit();

Answer 1

good thing but my problem not in declaration type
I want to write a list on a file but I don't know what is the type of object I have in the element

Answer 2

Try using decltype function.
template<typename T>
T func(T value) {}
dectltype(func(2)) v;
Here, dcltype returns the type of the return value of function func. (int in that example)

Answer 3

interested.....

Answer 4

Are all the types stored in your array derived from a common base class? If yes, then you can use polymorphism. Else... I don't know