Python - Why does trying and change "n" rise an exception?

Question

Result is "b2":
try:
s = ['a','c']
n = [0,2]
s[1:1] = 'b'
n[1:1] = 1
except:
pass
print(s[1],n[1])

Answer 1

n [1:1] is an iterable. So right hand side of equation must be an iterable too. 'b' is an iterable so we haven't exception for that.