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# In python ; how can i test if a character exist or not in a list that begin from 0 to 9 ... or from list a to z ?

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Diego i know that ; but i mean that can i write list a to z ? Python does'nt accept 'a'..'z' without writing all letters or all digits ?

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Diego thank you

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Seb TheS thank you

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print("a" in "0123456789") # False print("a" in "abcdefghijklmnopqrstuvwxyz") # True

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Abdelkader Barraj print("a"in [chr(i) for i in range(48,58)]) # False print("a" [chr(i) for i in range(97,123)]) # True

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Diego It's a test not a loop .. I whould like to test if a caracter is a letter or a number

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You can use regular expression (re), but for just a character, there is another solution: This is how to check whether a character is digit, uppercase or lowercase letter: function ord, returns an unique position of a character in a list of 2^16 (=65536) different characters. "0": 48, "9": 57 "A": 65, "Z": 90 "a": 97, "z": 122 You can test whether character is: A digit: 48 <= ord("7") <= 57 #True 48 <= ord("0") <= 57 #True 48 <= ord("A") <= 57 #False An uppercase character: 65 <= ord("F") <= 90 #True 65 <= ord("f") <= 90 #False 65 <= ord("9") <= 90 #False A lowercase letter: 97 <= ord("e") <= 90 #True 97 <= ord("z") <= 90 #True 97 <= ord("O") <= 90 #False

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Then you can use this information to check whether all, or atleast one of the characters in a list or a string is digit, lowercase letter or uppercase letter using any and all functions, and list comprehension. #All characters in "An abstract 123 class" must be digits. text = "An abstract 123 class" all(48 <= c <= 57 for c in text) #False #Atleast one character in "Abstract 123 class" must be an uppercase letter: any(65 <= c <= 90 for c in text) #True