Malloc

Question

What the following code does?
X=(int*)Malloc(sizeof(int)) * 6;
In c programming language...

Answer 1

Syed Waseem
When allocating memory dynamically in the heap malloc function is used, the function malloc retuns a handle which needs to be stored in a pointer to appropiate datatype
where X is an integer pointer you can do like this way too
int* ptr = (int*) malloc(sizeof(int) * 6);
X = (int*) malloc(6 * sizeof(int));
// 6 ints. Memory is allocated at the heap (a total of 24 bytes, assuming sizeof(int) is 4 bytes
when your task is completed then free the memory from being safe with memory leakage.
free(X)

Answer 2

Yes 6 integers with memory allocation of 24 bytes as pointer has defined data type as integer

Answer 3

Thanks,
For Your help...🤝

Answer 4

So, it returns total 6 int pointer to x...