Answer 1

import re

def multiple_replacements(i, x, mystring):
rep = {re.escape(k):v for k,v in zip(i,x)}

pattern = re.compile("|".join(rep.keys()))

text = pattern.sub(lambda m: rep[re.escape(m.group(0))], mystring)

return text

print(multiple_replacements(("1","2","3"),("6","7","2"),"1 * 2 = 43"))
# 6 * 7 = 42

Modified this code to work with Python 3.
https://stackoverflow.com/a/6117124

Answer 2

If you can put the substitution pairs in a dictionary, then the approach described here may work:
https://stackoverflow.com/questions/15175142/how-can-i-do-multiple-substitutions-using-regex-in-JUMP_LINK__&&__python__&&__JUMP_LINK

Another idea is that in the sub(pattern, repl, string) function, the repl parameter can actually be a function and a match object is passed to it automatically. So you can write a function to make the correct replacement.

You may also chain the sub function, something like:
sub(x1, x2, sub(y1, y2, string))
https://code.sololearn.com/c4d5quRYe9op/?ref=app

Answer 3

[1-6]

Answer 4

re.sub(‘{}’.format(x2), x1)
re.sub(‘{}’.format(y2), y1)

This should work. Notice I removed the ‘r’ from the string. It’s not necessary because you aren’t using any metacharacters or backslashes here, and I’m not sure if string’s ‘.format()’ method works on raw strings. If I’m misunderstanding your question, please let me know.

Answer 5

def sub(pttrns, strings):
for i, s in enumerate(strings):
re.sub(‘{}’.format(pttrns[i]), s)

like this? this will take 2 lists as args and will sub the string with the corresponding index

Answer 6

[1-6]

Answer 7

This is how I have written it.
Repeat the regex re.sub(re.sub())) twice within the regex to return different variable x2 and y2.

newstr = re.sub(r'x1', 'x2', re.sub(r'y1', 'y2', str))

https://code.sololearn.com/c0FSk8ZFn8r3/?ref=app