Exception specifying 🐍

Question

Story: (You can skip)
I wanted to add a testing mode to a program. I wanted the testing mode to return an integer in C style. (0 means a successful termination, while 1 means a "bad" termination.)
Problem.
I would want to print the error type in case of an error occurred, but I did not want to cause the program to terminate.
Question:
How can I print the error type without raising the error?
The 10 km long ladder of except blocks is not the wanted solution.

Answer 1

maybe something like this ? I believe it works but its extremely bad.
def error1():
return 1/0
def error2():
return 1+"1"
for i in [error1,1,"Hello,World",error2]:
try:
print(i())if callable(i)else print(i)
except Exception as e:
print(e)

Answer 2

If i understood you right, here's what i believe you mean (let me know if you need clarification):
import sys
try:
print(1/0) #or any error
except:
print(sys.exc_info()[1])

Answer 3

The as keyword is gold. I should have checked dir(Exception), because I did not know anything about with_traceback method.
Thank you.
I expected something much more complex.
The question is answered.