How the same code results in two answers?

Question

int[] a = {100, 89, 6, 3};
for (int i = 1; i < a.length; i++) {
a[i]=a[i-1] % a[i];
System.out.println (a[i]);
}
Output:
11
5
2
int[] a = {100, 89, 6, 3};
for (int i = 1; i < a.length; i++) {
System.out.println ( a[i-1] % a[i]);
}
Output:
11
5
0
I don't get it!!! 6%3 results in 0 but the 1st code gives me output 2!! But the second one gives the correct output!!
Edit : I got it 😅
It was my negligence
Thanks everyone for the answers

Answer 1

Notice carefully.
In the first loop, you're modifying the elements here,
a[i]=a[i-1] % a[i];
In the first run, i = 1:
a[1] = a[0] % a[1] => a[1] = 100 % 89 = 11
So, a = { 100, 11, 6, 3 }
In the second run, i = 2:
a[2] = a[1] % a[2] => a[2] = 11 % 6 = 5
So, a = { 100, 11, 5, 3 }
Lastly, in the third run, i = 3:
a[3] = a[2] % a[3] => a[2] = 5 % 3 = 2
which explains your first output ;)
While in the second code, you aren't assigning!

Answer 2

Because it's not the same code.

Answer 3

Thanks everyone 😅😅😅
My negligence