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How to delete a someone string

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5th Jun 2019, 5:14 AM
Taufiq9
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18 Answers
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var str="MBH help his friend"; var strCut=""; for(let i=9; i<19; i++) strCut+=str[i] alert(strCut)
5th Jun 2019, 5:41 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 2
Python 🙄😌 str="MBH help his friend" print(str[9:19])
5th Jun 2019, 5:42 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 2
str="MBH help his friend" print(str[9:19]) #🙄
5th Jun 2019, 5:44 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 2
str="other way" strCut="" for i in rang(6,9): strCut+=str[i] print(strCut) # way
5th Jun 2019, 5:54 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
Do you mean cut it?
5th Jun 2019, 5:29 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
Ok by JavaScript
5th Jun 2019, 5:32 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
var str="MBH help his friend"; alert(str.substr(9,17))
5th Jun 2019, 5:33 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
Or in other languages
5th Jun 2019, 5:34 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
I am talking about js but u use the last in python
5th Jun 2019, 5:43 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
No bro, this for js. I need for python3
5th Jun 2019, 5:43 AM
Taufiq9
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+ 1
his friend
5th Jun 2019, 5:50 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
See :: str="any thing" #first letter is a equal 0 and n = 1 ... print(str[4:9]) #4 5 6 7 8 9 equal thing ###
5th Jun 2019, 5:52 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
+ 1
Yea
5th Jun 2019, 5:52 AM
Basel.Al_hajeri?.MBH()
Basel.Al_hajeri?.MBH() - avatar
0
Yes, true
5th Jun 2019, 5:31 AM
Taufiq9
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0
For Python language
5th Jun 2019, 5:36 AM
Taufiq9
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0
What's output??
5th Jun 2019, 5:47 AM
Taufiq9
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0
Is there another way? besides that way ...
5th Jun 2019, 5:52 AM
Taufiq9
Taufiq9 - avatar
0
Ok thx:v
5th Jun 2019, 5:57 AM
Taufiq9
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