Please, Explain the following code...

Question

#include <iostream>
using namespace std;
template <class T>
void f(T) {
static int i=1;
cout<<++i;
}
int main() {
f(1);
f(1.0);
f(1);
return 0;
}
//Output is 223
//I was expecting 234

Answer 1

f is templated, so f(int) is not the same as f(double) or f(float).
Therefore f(int) and f(float/double) will have their own distinct static int i;
What you're used to is writing a function f(int) not templated and the compiler doing the implicit conversion for you when you call it f(1.0).

Answer 2

You're welcome :)

Answer 3

Paul oh that was the concept, ok thanks for your help i got it...