Can sm explain me 3D array and 4D array?

Answer 1

What do you mean

Answer 2

That code is private, and you should do it like this:
int arr3d[][][]
instead of:
int[][][] arr3d
I'm sorry, but I get all the languages mixed up sometimes

Answer 3

If you want that many elements, yes

Answer 4

Well, first you should understand 1D and 2D arrays.
A 1 dimensional array is just a normal array (like int[] arr1d).
A 2 dimensional array is an array, containing another array:
[1, 2, [3, 4, 5]]
You should declare it like this:
int[][] arr2d.
You can access its elements like this:
cout << arr2d[2][2]; //Outputs 4
More than two dimensional arrays don't need explanation, it's pretty obvious after that.
3D: int[][][] arr3d = [1, [2, [3, 4, 5]]];
arr3d[1][1][2] == 5
...

Answer 5

I'm sorry, are you sure that declared correctly?

Answer 6

Is it like that
int arr [2][2]={{1,2},/*0 row*/
{3,4}};/*1row*/
cout << arr [2][2];
// Outputs 0

Answer 7

Okay, I used brackets instead of curly brackets, but you get the point

Answer 8

Not fully

Answer 9

I do know 2d arr very well, but 3d and 4D is little bit complex for me

Answer 10

Anyway thxs for explanation

Answer 11

Btw Airree u explained me incorrectly

Answer 12

Look at my codes .There s code "3D array". Maybe through that you will see your mistake

Answer 13

Ok

Answer 14

You mean that I should declare like this:
int [2][3][4] arr3D

Answer 15

?

Answer 16

Got.

Answer 17

Let me just understand better through the coding