Output displayed twice

Question

In the code below the output is displayed twice. Can somebody please tell me why it is working this way and how to fix it.
https://code.sololearn.com/ccRi7rCk7HkA/?ref=app

Answer 1

// Make something like the following
// 1. Remove else statement
// 2. When you find at least one pair exit the program
// 3. in case that the program does not find any pair , raise message
for(int i=1;i<p;i++){
for (int j=1;j<p;j++){
x=i*j;
if(p==x){
y=i+j;
if(s==y){
cout << "\n" << s << " and " << p << " are sum and product of " << i << " and " << j << endl;
return 0;
}
}
}
}
cout << s << " and " << p << " are invalid input."<< endl;

Answer 2

Vasiliy I am new to coding. I was just trying to do it correctly. Can you code it and explain ? (coditional branch )

Answer 3

This is awesome bro.. 😍😍 Bennett Post . but there is one thing if we check for 4,5 i.e 1*4=4 & 1+4=5 then it is giving invalid output ..

Answer 4

Vasiliy it is not working properly.. I tried with 5,6 because that was the example given in question. something is wrong 🤔

Answer 5

🤦🏻‍♂️ 5 is sum of two numbers and 6 is product of same two numbers .. i.e 2,3 . I think I didnt wrote question clearly. 😰

Answer 6

lol yes 😁

Answer 7

In this case, it is sufficient in the proposed Prokopios Poulimenos code to change the variable "p" in cycles to "s".

Answer 8

Night_fury~
Sorry, I misunderstood the task, thanks for the additional explanation.

Answer 9

have you tried snapping your fingers? *Jk*

Answer 10

Why do you use as many as two cycles, when you can do through one conditional branching: "if...else"

Answer 11

According to the task: "Two numbers are given one is the sum of two integers and another is product of the same integers. FInd the two integers." 5, 6 - invalid input. 😕