Debug

Question

I'm not able to identify the error
If it is 1 then Monday must be printed.
It 2 then Tuesday
https://code.sololearn.com/cb2U0ikJCWp1/?ref=app

Answer 1

Change code at line 4 to
char* str;
The char array was a local variable, it can't be transferred outside the function.
Loniie on second thought, I think you might be better to follow suggestion from Anna , I'm not so sure what I gave you was technically correct, I just passed in what I found to be working : )

Answer 2

You can't assign strings to variables like that, use strcpy(str, "Monday") etc. instead (you'll need to #include <string.h>).
I'm not sure if functions can return strings (=char arrays, they probably can't). You can use a pointer to a global variable instead:
char *day_str[100]; // global
void day(int n)
{
switch (n)
{
case 1:
strcpy(day_str, "monday"); // change global variable
//str="monday";
break;
case 2:
//str="tuesday";
break;
default:
//str="invalid";
break;
}
}
int main() {
int n=0;
scanf("%d",&n);
day(n); // set global variable
printf("%s",day_str); // and print it
}

Answer 3

Thank you thank you so much