[python][help] illegal target for varible annotation

Question

not sure what im doing wrong here? I'm trying to reference variable "operand" to get a math function to perform the sum.
only just started learning python variables havent learn if statements yet
<code>
num1 = input("enter the first number")
operand = input(" what operation would you like to use")
num2 = input("please enter your second number")
if operand == "+":
print(int(num1)+int(num2))
elif operand == "-":
print(int(num1)-int(num2))
elif operand == "*":
print(int(num1)*int(num2))
elif operand == "x":
print(int(num1)*int(num2))
elif operand == "X":
print(int(num1)*int(num2))
elif operand == "/":
print(int(num1)/int(num2))
elif operand == "%":
print(int(num1)%int(num2))
</code>

Answer 1

Your indentation is wrong.
It should look like this:
if...
...
elif...
....
elif
....

Answer 2

Yes, but all the other elifs need to be aligned, because they stand in relation to each other.
Whenever there's a colon, what follows needs to be indented.

Answer 3

for example by asking with an if-condition:
if operand not in ('+', '-', '*' [and so on]) :
print('Wrong input!')

Answer 4

For numbers you can check it creating a finction as below :
def inputNumber(message):
while True:
try:
userInput = int(input(message))
except ValueError:
print("Not an integer! Try again.")
continue
else:
return userInput
break
So your code will be modified as
num1 = inputNumber("enter the first number\n")
operand = input("what operation would you like to use\n")
num2 = inputNumber("please enter your second number\n")

Answer 5

Try to cast the input to int
and remove the int from print function
Check below
https://code.sololearn.com/c54yj37FYSBQ/#py

Answer 6

how do i check if the user has enterend in numbers and/or an acceptable operand

Answer 7

Thankyou so much 😄😄

Answer 8

So it's the print statement that needs to be indented