For( char c=0;c<256;++c){}

Question

Why this code run in infinity time

Answer 1

It is infinite in C/C++ because a char is 1 byte and its range is -128 to 127 for signed and 0 to 255 if unsigned, both of these ranges are always less than 256 so the condition is always true.
In java I think a char is 2 bytes so it doesn't have this issue... at least not until 65536 ( if unsigned ). :)

Answer 2

After c is 127 the next increment updates the value of c to -128 which still satisfies the loop condition.
https://code.sololearn.com/c6RfNKr2a22w/?ref=app

Answer 3

Your code does not run infinity.
https://code.sololearn.com/cWrccvH9N0v5/?ref=app
I think this works because every char has an ascii value --> ++c increment the ascii value of c

Answer 4

Dennis Thx. I didn't know this fact.

Answer 5

Your code, use int instead of char if you wanna count from 0 to 255:
for(int c = 0;c <256;c++){
System.out.println(c);
}
Wanna loop through characters?
for(char c = 'A';c <'Z';c++){
System.out.println(c);
}