Why don't #include <...> require a semicolon?

Question

Programming Language:
C & C++
Repeat:
Why don't #include <...> require a semicolon?
Possible reason?:
Because like in function definition or class declaration you don't need to have semicolon after the codeblock.

Answer 1

#includes and other # are part of the preprocessor and is run before the compilation phase.
For a #include, code that is going to be included is copy pasted there which has their own ;'s.
Also for functions, classes and loops { } are used to mark the end instead of ; and at the end of a class a ; is required because there is another field after the } that needs to be closed.

Answer 2

I think that's because that part of the code isn't intended for the compiler but for the preprocessor which uses its own syntax. I only know that you can't use a semicolon after #define because that would insert semicolons everywhere in the code. #define NUM 50; would lead to every "NUM" being replaced with "50;", not "50" 😶

Answer 3

Preprocessor directives don't need semicolons.

Answer 4

Ipang answers for your guestions cleared something for me too.

Answer 5

Dennis I saw such examples for structures, I didn't know classes can be treated the same 😁
Thanks Dennis,
Seb TheS , sorry, didn't mean to hijack, was just looking for clarity 👍

Answer 6

Dennis There is another field at the end of class definition block? what field is that please?
class MyClass {
...
} < a field in here? >;

Answer 7

Ipang Yea, you can specify object names after the }, seperated by ,'s, which are then constructed immediately.
You can get away with anonymous classes that way. :)