Array in parameters of a function?

Question

i need help, i dont know how i can do this.

Answer 1

//What's the problem?

//If you want array to be passed as the argument commonly the array name and length of the array is passed(There is difference between parameter and argument).

//here is a sample that
void func(array_name, length){
for(i = 0; i <length ; i++){
cout << "Array values: " << array_name[i]<< endl;
}
}
//this function prints the elements in an array.

Answer 2

Did you mean like this code?
https://code.sololearn.com/cUp9dSnT5Z9U/?ref=app

Answer 3

int seq[] = {1, 2, 3};

void foo(int* begin, int* end);
foo(seq, seq + 3);

void bar(int arr[], int size);
bar(seq, 3);

As an argument, an array name decays to a pointer to it's first element, so there's not much difference between foo and bar.

Answer 4

If a size of an array is known at compilation time you can also do the following.

https://code.sololearn.com/cU2T7Z6T5WKh/?ref=app