c++ char truncation

Question

Can someone explain why the variable has been truncated to 232?
A char is 8 bits, so why not to 255
https://code.sololearn.com/cJDB8jQKcjQ7/?ref=app

Answer 1

It's modulo. 1256 % 256 == 232
Basically everything that doesn't fit into 8 bits gets cut off. 1256 is 10011101000 in binary and the leftmost 3 bits are too much. What's left over is 232.
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EDIT: Another way to say it is that you start at 0 and keep counting up. Once you hit 255 you then reset to 0 again. If you've counted up 1256 times you end up at 233.