Can't wrap my head around Increment and Decrement operation

Question

I have the following code
#include <iostream>
using namespace std;
int main() {
int x = 5;
int y = 6;
x++;
++x;
y++;
++y;
cout << x << endl;
cout << x << endl;
cout << y << endl;
cout << y << endl;
return 0;
}
If I compile and run I get this
7
7
8
8
why am I getting 7 instead of 6 after x++ gets executed?

Answer 1

Because "cout" is after 2 increments

Answer 2

x++ is postfix increment operator, as Anna told x++ will first use its value then it will increment it.
int x = 5;
cout << x++ << endl ;
cout << x << endl ;
Output :
5 //First used(print) its value
6 //Then incremented on next statement

Answer 3

x++ means that x is incremented immediately. It's the same as x += 1 or x = x + 1. If used in an assignment like y = x++, x will be assigned to y first and then incremented.
y = ++x means that x is incremented before it is assigned to y. If you don't use it in an assignment, x++ is pretty much the same as ++x.
Note that you only cout x after it was incremented twice. So it's 5+2

Answer 4

After x++ is executed, the value of x is also incremented by 1. Why would it be 6?